-3x^2+300x-5000=0

Solution for -3x^2+300x-5000=0 equation:

-3x^2+300x-5000=0

a = -3; b = 300; c = -5000;
Δ = b2-4ac
Δ = 3002-4·(-3)·(-5000)
Δ = 30000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{30000}=\sqrt{10000*3}=\sqrt{10000}*\sqrt{3}=100\sqrt{3}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(300)-100\sqrt{3}}{2*-3}=\frac{-300-100\sqrt{3}}{-6}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(300)+100\sqrt{3}}{2*-3}=\frac{-300+100\sqrt{3}}{-6}
$